![Berger | Dillon 〉 on Twitter: "For those who are curious, the integral of sin(x)/x does *not* need contour integration to be evaluated Just needs a bit of creativity 😀 https://t.co/0AxFSPWdyw" / Berger | Dillon 〉 on Twitter: "For those who are curious, the integral of sin(x)/x does *not* need contour integration to be evaluated Just needs a bit of creativity 😀 https://t.co/0AxFSPWdyw" /](https://pbs.twimg.com/media/D8PcPnoUcAAzCB8.jpg:large)
Berger | Dillon 〉 on Twitter: "For those who are curious, the integral of sin(x)/x does *not* need contour integration to be evaluated Just needs a bit of creativity 😀 https://t.co/0AxFSPWdyw" /
![Given that integral of (sinx)/x= pi/2 (limit= 0 to infinity) Then prove that integral of ((sin x)^3)/x = - Maths - Integrals - 14533001 | Meritnation.com Given that integral of (sinx)/x= pi/2 (limit= 0 to infinity) Then prove that integral of ((sin x)^3)/x = - Maths - Integrals - 14533001 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/content_ck_images/ck_5eb96d2e2b243.jpg)
Given that integral of (sinx)/x= pi/2 (limit= 0 to infinity) Then prove that integral of ((sin x)^3)/x = - Maths - Integrals - 14533001 | Meritnation.com
![calculus - Difficulties understanding a proof of $\int_0^{\infty} \frac{\ sin(x)}{x} \, dx = \frac{\pi}{2}$ - Mathematics Stack Exchange calculus - Difficulties understanding a proof of $\int_0^{\infty} \frac{\ sin(x)}{x} \, dx = \frac{\pi}{2}$ - Mathematics Stack Exchange](https://i.stack.imgur.com/RUp17.png)