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The mean value of integral ( sin theta d theta) where the limit is pie to 0 is
SOLVED: Use integration by parts to evaluate | sin-'(2x) dx X sin -1 (2x) 4x2 2 +C X sin '(2x) V1-4x2 +c 2 X sin (2x) -4x2 +C sin M(2x) +C 2 4X
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![Let x = f\"(t)cos t + f(t)sin t and y = - f\"(t)sin t + f'(t)cos t. Then int [ (dx/dt)^2 + (dy/dt)^2 ]^ 12dt equals](https://dwes9vv9u0550.cloudfront.net/images/2054189/5944209b-fa94-4b70-b9cb-27532bd52011.jpg "Let x = f\\"(t)cos t + f(t)sin t and y = - f\\"(t)sin t + f'(t)cos t. Then int [ (dx/dt)^2 + (dy/dt)^2 ]^ 12dt equals")
Let x = f\"(t)cos t + f(t)sin t and y = - f\"(t)sin t + f'(t)cos t. Then int [ (dx/dt)^2 + (dy/dt)^2 ]^ 12dt equals
How do you integrate (sinx)^2 dx? | Socratic
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Ex 7.8, 4 - Direct Integrate sin 2x dx from 0 to pi/4 - Ex 7.8
int sin^4(2x)dx
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